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Algebra / Linear equations in two variables Difficulty: Easy

$y = - 4 x + 40$

Which table gives three values of $x$ and their corresponding values of $y$ for the given equation?

$x$	$y$
$0$	$0$
$1$	$negative 4$
$2$	$negative 8$

$x$	$y$
$0$	$40$
$1$	$44$
$2$	$48$

$x$	$y$
$0$	$40$
$1$	$36$
$2$	$32$

$x$	$y$
$0$	$0$
$1$	$4$
$2$	$8$

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Explanation

Choice C is correct. Each of the given choices gives three values of $x$ : $0$ , $1$ , and $2$ . Substituting $0$ for $x$ in the given equation yields $y = - 4 (0) + 40$ , or $y equals 40$ . Therefore, when $x equals 0$ , the corresponding value of $y$ for the given equation is $40$ . Substituting $1$ for $x$ in the given equation yields $y = - 4 (1) + 40$ , or $y equals 36$ . Therefore, when $x equals 1$ , the corresponding value of $y$ for the given equation is $36$ . Substituting $2$ for $x$ in the given equation yields $y = - 4 (2) + 40$ , or $y equals 32$ . Therefore, when $x equals 2$ , the corresponding value of $y$ for the given equation is $32$ . Choice C gives three values of $x$ , $0$ , $1$ , and $2$ , and their corresponding values of $y$ , $40$ , $36$ , and $32$ , respectively, for the given equation.

Choice A is incorrect. This table gives three values of $x$ and their corresponding values of $y$ for the equation $y = - 4 x$ .

Choice B is incorrect. This table gives three values of $x$ and their corresponding values of $y$ for the equation $y = 4 x + 40$ .

Choice D is incorrect. This table gives three values of $x$ and their corresponding values of $y$ for the equation $y equals 4 x$ .